(u+4)^2=2u^2+13u+20

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Solution for (u+4)^2=2u^2+13u+20 equation: 



(u+4)^2=2u^2+13u+20

We move all terms to the left:

(u+4)^2-(2u^2+13u+20)=0

We get rid of parentheses

-2u^2+(u+4)^2-13u-20=0

We add all the numbers together, and all the variables

-2u^2-13u+(u+4)^2-20=0

We move all terms containing u to the left, all other terms to the right

-2u^2-13u+(u+4)^2=20

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